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3 years ago

Which of the following could be the equation of the function below?

Mathematics

2 answers:

rodikova [14]3 years ago

8 0

Answer:

y = 0.5 cosine (4 (x - pi/2)) - 2

Step-by-step explanation:

Taking the general form:

y = A cosine (Bx - Cπ)) + D

In the following case. the constants are:

y = 0.5 cosine (4x - 2π)) - 2

A: 0.5

B: 4

C: 2π

D: -2

The range of this function is:

range = [-|A|+D, |A|+D]

range = [-0.5-2, 0.5-2]

range = [-2.5, -1.5]

Which coincides with "It has a maximum at negative 1.5 and a minimum at negative 2.5"

At x = 0, the function value is:

y = 0.5 cosine (4(0) - 2π)) - 2

y = 0.5 - 2 = -1.5

As indicated in "a curve crosses the y-axis at y = negative 1.5"

The period of the function is:

period: 2π/B

period = 2π/4 = π/2 or 2 cycles at π

as described in "It goes through 2 cycles at pi."

Art [367]3 years ago

3 0

Answer:

C. Y=0.5 cosine(4(x-pi/2))-2

Step-by-step explanation:

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Rally sold 30 flower baskets at a market. She purchased 30 baskets for $142.65, 185 yards of ribbon for $.07 per yard, and $252.

rosijanka [135]

Answer:

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3 years ago

What is the inverse of the function f(x) = 2x + 1?

BaLLatris [955]

Answer:

$f^{-1} = \frac{x-1}{2}$

Step-by-step explanation:

$f(x) = 2x+1$

Replace it with y

$y = 2x+1$

Exchange the values of x and y

$x = 2y+1$

Solve for y

$x = 2y+1$

Subtracting 1 from both sides

$2y = x-1$

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Replace it by $f^{-1}$

So,

$f^{-1} = \frac{x-1}{2}$

3 0

3 years ago

Read 2 more answers

Y= x^2 -5 solve for x

dexar [7]

$Y= x^2 -5$

We need to solve for x, we need to get x alone

$Y= x^2 -5$

Lets start by removing -5

Add 5 on both sides

$y + 5= x^2 -5 + 5$

$y + 5= x^2$

Now to isolate x , we need to remove the square from x

To remove square , take square root on both sides

$+-\sqrt{y+5} = \sqrt{x^2}$

square and square root will get cancelled

$+-\sqrt{y+5} = x$

So $x = +\sqrt{y+5}$ and $x = -\sqrt{y+5}$

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3 years ago

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ss7ja [257]

Answer:

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Answer:

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2 years ago