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mezya [45]
3 years ago
12

Which of the following could be the equation of the function below?

Mathematics
2 answers:
rodikova [14]3 years ago
8 0

Answer:

y = 0.5 cosine (4 (x - pi/2)) - 2

Step-by-step explanation:

Taking the general form:

y = A cosine (Bx - Cπ)) + D

In the following case. the constants are:

y = 0.5 cosine (4x - 2π)) - 2

A: 0.5

B: 4

C: 2π

D: -2

The range of this function is:

range = [-|A|+D, |A|+D]

range = [-0.5-2, 0.5-2]

range = [-2.5, -1.5]

Which coincides with "It has a maximum at negative 1.5 and a minimum at negative 2.5"

At x = 0, the function value is:

y = 0.5 cosine (4(0) - 2π)) - 2

y = 0.5 - 2 = -1.5

As indicated in "a curve crosses the y-axis at y = negative 1.5"

The period of the function is:

period: 2π/B

period = 2π/4 = π/2 or 2 cycles at π

as described in "It goes through 2 cycles at pi."

Art [367]3 years ago
3 0

Answer:

C. Y=0.5 cosine(4(x-pi/2))-2

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

We have been given the demand equation for Turbos as q=-4p+544, where q is the number of buggies the company can sell in a month if the price is $p per buggy.

Let us find revenue function by multiplying price of p units by demand function as:

Revenue function: pq=p(-4p+544)

pq=-4p^2+544p

Since revenue function is a downward opening parabola, so its maximum point will be vertex.

Let us find x-coordinate of vertex using formula \frac{-b}{2a}.

\frac{-b}{2a}=\frac{-544}{2\times -4}

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The maximum revenue would be the y-coordinate of vertex.

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Therefore, the company should sell each buggy for $68 to get the maximum revenue of $18,496.

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3 years ago
which of the following formulas would find the lateral area of a right cylinder where h is the height and r is the radius
vlada-n [284]

Answer:

B. LA=2\pi rh

Step-by-step explanation:

The lateral area of the right cylinder refers to the curved surface area.

The lateral area of the right cylinder does not include the two circular bases.

The lateral area is given by the formula;

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