Answer:
The second option is the correct answer
The sequence is : 0, -1, -6, -31, -156
Step-by-step explanation:
It is given that,
The recursive formula , an = 5a(n-1) - 1 and a1 = 0
<u>To find a2, a3, a4, a5
</u>
a2 = 5a1 -1 = 5x0 - 1 = -1
a3 = 5a2 - 1 = (5x -1 ) - 1 = - 5 - 1 = -6
a4 = 5a3 - 1 =(5x -6) - 1 = -30 - 1= -31
a5 = 5a4 - 1 = (5 x -31 ) - 1 = -155 -1 = -156
Therefore the resulting sequence is
0, -1, -6, -31 ,-156
Answer:
The son is 5 I think
Step-by-step explanation:
24+3=27
27 divided by 5 = 5.4
round 5.4 to 5 since it is under .5
and you get 5
Answer: 
We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.
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Explanation:
It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.
I'm going to use these three log rules, which apply to any base.
- log(A) + log(B) = log(A*B)
- log(A) - log(B) = log(A/B)
- B*log(A) = log(A^B)
From there, we can then say the following:

Answer:
The answer is C
Step-by-step explanation:
Possible outcomes: 5040
Possible to begin with a 0: 504
Theoretical probability: 0.1
These are the correct answers