Let's factorise it :

![\: {\qquad \dashrightarrow \sf {x}^{3} (x + 3) + [-5(x + 3)] }](https://tex.z-dn.net/?f=%5C%3A%20%7B%5Cqquad%20%20%5Cdashrightarrow%20%5Csf%20%20%20%20%7Bx%7D%5E%7B3%7D%20%28x%20%2B%203%29%20%2B%20%5B-5%28x%20%2B%203%29%5D%20%20%7D)
Using Distributive property we get :



⠀
Therefore,

Answer:
y = 20/3
Step-by-step explanation:
4y + 2y + 10 = 50
Combine like terms on the left side.
6y + 10 = 50
Subtract 10 from both sides.
6y = 40
Divide both sides by 6.
y = 40/6
Reduce the fraction by dividing the numerator and denominator by 2.
y = 20/3
Answer:
10010
Step-by-step explanation:


So
gives us:



-----------------------------------------------------
Combine like terms:


We aren't allowed to have a coefficient bigger than 1.
I'm going to replace
with 1 and
with
:

I want a
number:

Combine like terms:

:

Combine like terms:

We can rewrite the first term by law of exponents:


So the binary form is:

Maybe you like this way more:
Keep in mind 1+1=10 and that 1+1+1=11:
Setup:
1 0 1 1
+ 1 1 1
------------------------------
(1) (1) (1)
1 0 1 1
+ 1 1 1
------------------------------
1 0 0 1 0
I had to do some carry over with my 1+1=10 and 1+1+1=11.
Value of x is -1
The correct first step to solving the inequality is distributing the -4 into the para thesis