<span>we know that if 95 is out of 100%, we can write it down as 95 = 100%. w</span><span>e also know that x is 20% of the output value, so we can write it down as x = 20%. </span>
now we have the equations:
95=100%
x=20%
next we will put the equations together
95/x = 100%/20%
95/x=100/20
<span>(95/x)*x=(100/20)*x
</span>we multiply both sides of the equation by x
<span>95=5*x
</span>now we divide both sides of the equation by 5 to get x
<span>95/5=x </span>
<span>19=x </span>
x=19
we now know that <span>20% of 95 = 19
let me know if you have any other questions
:)</span>
Answer:
Midpoint (-2,4)
distance nearest tenth = 8.9
The approximate distance = 9
Step-by-step explanation:
Formulas
PQ midpoint = (x2 + x1)/2, (y2 + y1)/2
distance d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )
Givens
x2 = -4
x1 = 0
y2 = 1
y1 = 7
Solution
M(PQ) = (-4+0)/2, (1 + 7)/2
M(PQ) = -2, 4
The midpoint is -2,4
The distance = sqrt( (4 - 0)^2 + (1 + 7)^2 )
The distance = sqrt(16 + 64)
The distance = sqrt(80)
The distance = 4√5 exactly
The distance = 8.94
The distance = 8.9 To the nearest tenth
Question 2
The distance is rounded to the nearest whole number which is 9.
Answer:
-21
Step-by-step explanation:
- * + = -
- * - = +
+ * + = +
Here + * - = -
7* 3 = 21 and sign is -ve
Answer:
a = 16.733
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2
a^2 + 9^2 = 19^2
a^2 = 19^2 - 9^2
a^2 = 361-81
a^2 =280
Taking the square root of each side
sqrt(a^2) = sqrt(280)
a = 16.73320053
Rounding to the nearest thousandth
a = 16.733
Answer:
5
Step-by-step explanation:
To find B and C prime, you must multiply them by .25, or 1/4.
B' =
(-2 x .25),(1 x .25)
I did mine in fraction form, because it will prove to be more useful in future mathematics.
B' = (1/2 , 1/4)
Repeat the process with C.
C' =
(14 x .25),(17 x .25)
C' =
(7/2 , 17/4)
You only need to focus on B and C because you are finding the length of B'C'.
The formula for distance is the square root of x to the sub of 2 minus x to the sub of 1 squared minus y to the sub of 2 minus y to the sub of 1 square.
x2 - x1 = 7/2 - 1/2 = 6/2 = 3 squared = 9
y2 - y1 = 17/4 - 1/4 = 16/4 = 4 squared = 16
16 + 9 = 25
Square root of 25 is 5.
Therefore, the distance is 5.
