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3 years ago

Nicole usually scores between 89%

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

6 0

Answer:

Step-by-step explanation:

Nicole usually scores between 89% and 100% on her math quizzes.

On the quizzes she takes right after a track meet, she has about an 11% decrease in her score, so she will earn 100% - 11% = 89% of her usual score.

1. 89% of 89% is

$0.89\cdot 89\%=79.21\%\approx 79\%$

2. 89% of 100% is

$0.89\cdot 100\%=89\%$

So, if Nicole had a track meet the day before a quiz, her score would be between 79% and 89%.

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Use the triangle below to find cos V.

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Answer:

$cos\ V = \frac{2\sqrt{29}}{29}$

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

$cos\theta = \frac{Adjacent}{Hypotenuse}$

In this case:

$cos V= \frac{TV}{UV}$

Where

$TV = 6$

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$UV^2 = TV^2 + TU^2$ -- Pythagoras

$UV^2 = 6^2 + 15^2$

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Take square roots

$UV = \sqrt{261$

$UV = \sqrt{9*29$

$UV = \sqrt{9} *\sqrt{29$

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So:

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$cos\ V = \frac{2}{\sqrt{29}}$

Rationalize:

$cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}$

$cos\ V = \frac{2\sqrt{29}}{29}$

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