1.D
2.C
3.B
If you need to know the amount let me know.
Neither of those work for that equation
Answer:
0.1319 or 13.2%
Step-by-step explanation:
You can solve this using the binomial probability formula.
The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.
Then, we can set the equation as follows:
P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k)
n=4, x=2, k=2
when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157
when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154
when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008
Add them up, and you should get 0.1319 or 13.2% (rounded to the nearest tenth)
Answer:
225 frogs
Step-by-step explanation:
Total population of frogs = 300 frogs.
Observed population of frogs = 24
6 of the 24 observed frogs had spots
Which means , the number of frogs that did not have spots = 24 - 6 = 18 frogs.
We were told to find how many of the total population can be predicted to NOT have spots. We would form a proportion.
If 24 frogs = 18 frogs with no spots
300 frogs = Y
Cross multiply
24Y = 300 × 18
Y = (300 × 18) ÷ 24
Y = 5400 ÷ 24
Y = 225 frogs.
This means out of 300 frogs, 225 frogs do not have spots.
Therefore, the total population that can be predicted to NOT have spots is 225 frogs.
the total population can be predicted to NOT have spots
