All categories

3 years ago

WHAT IS THE EQUATION ?? AND TELL ME HOW YOU GOT IT.

Mathematics

1 answer:

tigry1 [53]3 years ago

6 0

Answer:

SUM OF ALL ANGLES OF A TRIANGLE =180

THEREFORE,

X+8+2X-3+6X-5=180

9X=180

X=20.

THEREFORE,<J=X+8=20+8=28

<K=6X-5=6*20-5=120-5=115

<L=2X-3=2*20-3=40-3=37.

You might be interested in

A girl kick a soccer ball 10 ft away from her, it came right back after she kicked the ball.How is that possible?

blondinia [14]

The windffffff#r ddccvxv ffffbdtgpruc

6 0

2 years ago

Guys please help, does this look ok? :)<br>I'll give brainliest as well <3

Sidana [21]

Answer:

it looks good

Explanation:

3 0

3 years ago

Read 2 more answers

construct a two column proof proving SM RN, given RM SN and ∠MRS ∠NSR. Submit the entire proof to your instructor.

AveGali [126]

I cannot see the column please text me

8 0

3 years ago

Lisa treated her sisters to lunch their lunch cost $75 and the sales tax was 8% if Lisa left

Molodets [167]

Answer:

djdjdjfjfjf

Step-by-step explanation:

kfkfkffikf

5 0

2 years ago

Sum of cubes: (a b)(a2 – ab b2) = a3 b3 Difference of cubes: (a – b)(a2 ab b2) = a3 – b3 Which products result in a sum or diffe

valentina_108 [34]

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

$(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3$

(a)

$(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\$

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

$(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

$(x+1)(x-1)=x^{2}-1^{2}\\$

we can say that this is neither sum nor difference of cube as it's difference of squares.

(d)

$(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)$

by comparison with formula this is equal to

$x^{3}+4^{3}\\$

Hence this is sum of cubes

(e)

$(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

To know more about cubes visit: brainly.com/question/107100

8 0

2 years ago