Answer:
Step-by-step explanation:
Assuming this complete question:
"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean kilograms and standard deviation kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.
"
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where and
And the best way to solve this problem is using the normal standard distribution and the z score given by:
We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.
We can convert the corresponding z score for x=42.6 like this:
So then the corresponding z scale would be:
Answer:
x=19(rounded) or 18.7882942281
Step-by-step explanation:
a^2+b^2=C^2
8^2+17^2=C^2
64+289= C^2
353=C^2
18.7882942281= C
19= C
I guess that u = μ & that a=σ. If so:
μ =100 & that σ =20 & x=20
Z score = (x-μ) / σ ==> Z score = (90-100)/20 ==> Z = - 0.5
Answer:
if they are both equeal
Step-by-step explanation:
Answer:
2/4
Step-by-step explanation:
Bonnie and Maria combined = 1/4 + 2/4 = 3/4
Gracie run = 5/4
=> How much farther, f, did Gracie run than Bonnie and Maria combined
= 5/4 - 3/4 = 2/4
So Gracie run 2/4 more than Bonnie and Maria combined