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Annette [7]
4 years ago
13

Suppose two dice (one red, one green) are rolled. Consider the following events. A: the red die shows 1; B: the numbers add to 4

; C: at least one of the numbers is 3; and D: the numbers do not add to 9. Express the given event in symbolic form. HINT [See Example 5.]
Either the numbers add to 9 or the red die shows a 1.

D ∩ B

D ∩ A

D' ∪ A

D' ∩ A

D' ∪ B

How many elements does it contain?
Mathematics
1 answer:
kirill115 [55]4 years ago
5 0

Answer: Third option is correct.

Step-by-step explanation:

Since we have given by

Event A: the red die shows 1

Event B :  the numbers add to 4

Event C: at least one of the numbers is 3

Event D : the numbers do not add to 9.

D' means the number add to 9.

We need to write the following statement in symbolic form:

Either the numbers add to 9 or the red die shows a 1.

So, it becomes,

D'\cup A

Number of elements in D'∪A = 1.

Hence, Third option is correct.

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Answer:

blank 1: 2xy(4x-5y)+3(4x-5y)

blank 2: (2xy+3)(4x-5y)

Step-by-step explanation:

Using factoring group to factor the polynomial 8x²y−10xy²+12x−15y

Step 1: Group the polynomial function

(8x²y−10xy²)+(12x−15y)

Step 2: Factor the common value and variables from the functions in parentheses.

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Step 3: Rearrange the expression by selecting one of the function in parentheses and combine those not in parenthesis.

(2xy+3)(4x-5y)

The final expression gives the factor form of the polynomial.

Hence the statement for each blank that correctly completes Lana's work are;

blank 1: 2xy(4x-5y)+3(4x-5y)

blank 2: (2xy+3)(4x-5y)

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