Answer:
A
Step-by-step explanation:
Hopefully this helps
<span>Not all functions will have intercepts</span>
Answer:

Step-by-step explanation:
<u>Trigonometric Ratios
</u>
This problem will be solved by the use of a trigonometric ratio called sine because it relates the opposite side of a given angle with the hypotenuse of the triangle.
Selecting the angle of 60° in triangle ABD:
<em>Sine Ratio
</em>


Solving for BD:

Since


Simplifying:

Hope it helps you !!!!!!! And if you want the step I will show you