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Svetllana [295]
3 years ago
12

A swimming pool is 72.25 feet long and 51.5 feet wide how much longer is the pool than it is wide

Mathematics
1 answer:
shepuryov [24]3 years ago
5 0

Hello, I am papaguy your answer is ready!

Answer: 20.75 feet


Explanation:


First of all, let's write down the length and the width of the swimming pool:


- Length:


- Width:


The problem is asking us to find how much longer is the pool than it is wide, so it is basically asking us to find the difference between the length and the width of the pool, which is equal to:




So, the answer is 20.75 feet.


Best of luck!


If you loved this answer why not click that cool mark brainliest button!

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Write the equation of a line in the slope-intercept form that has a slope of 4 and contains the point (4, 12).
vekshin1

Answer:

y=4x-4

Step-by-step explanation:

Hi there!

we are given that a line has a slope of 4 and it contains the point (4, 12)

We want to write the equation of this line in slope-intercept form

Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept

As we are already given the slope, we can immediately substitute it into the formula.

Replace m with 4 in y=mx+b:

y=4x+b

Now we need to find b

As the equation passes through the point (4, 12), we can use it to help solve for b

Substitute 4 as x and 12 as y:

12 = 4(4) + b

Multiply

12 = 16 + b

Subtract 16 from both sides

-4 = b

Substitute -4 as b

y = 4x - 4

Hope this helps!


Topic: Finding the equation of the line

See more on this topic here: brainly.com/question/27539102

7 0
2 years ago
The month of July has 31 days. What is the greatest
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3 years ago
How do you find the area of the shaded sector of the circle? The radius is 10in and the sector is 45 degrees
Step2247 [10]

Given:

Radius of the circle = 10 in

Central angle of the sector = 45 degrees

To find:

The area of the sector.

Solution:

Area of a sector is

A=\dfrac{\theta}{360^\circ}\pi r^2

Where, \theta is the central angle in degrees.

Putting r=10 and \theta=45^\circ, we get

A=\dfrac{45^\circ}{360^\circ}\pi (10)^2

A=\dfrac{1}{8}\pi (100)

A=12.5\pi

Therefore, the area of the sector is 12.5π sq. inches.

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