3 years ago

Solve: 15 = -(1/2)(-12x + 2)

Mathematics

1 answer:

notsponge [240]3 years ago

6 0

your answer is: = 8/3

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Find the slope of the line passing through the points<br> (-6,-5) and (4,4)

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Answer:

$\frac{9}{10}$

Step-by-step explanation:

The slope formula is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

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For what value of constant c is the function k(x) continuous at x = 0 if k =

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The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:

$\mathbf{ \lim_{x \to 0^-} k(x) = \lim_{x \to 0^+} k(x) = 0 }$

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= c }$

Provided that:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }$

Using l'Hospital's rule:

$\mathbf{\implies \lim_{x \to 0} \ \ \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}= \lim_{x \to 0} sec \ x \ tan \ x = 0}$

Therefore:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}=0 }$

Hence; c = 0

Learn more about the limit of a function x here:

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Answer:

$\text{A. }\cos \theta = \frac{3}{5}$

Step-by-step explanation:

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