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Cerrena [4.2K]
3 years ago
8

Fatema loves to run marathons. The last one she participated in took her 2 hours to complete. The year before (2016) , she compl

eted the same marathon in 8/11 of the time and the year before that (2015) she completed it in 9/12 of the time. What year did Fatema run the fastest? JUSTIFY YOUR ANSWER PLEASE I NEED HELP ASAP!
Mathematics
1 answer:
Lelechka [254]3 years ago
3 0
2017 = 2 hrs x 60 mins = 120 mins
2016 = 8/11 x 120 mins = 87.27 mins
2015 = 9/12 x 120 mins = 90 mins

Therefore, Fatema ran the fastest in 2016.
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Brainliest to first correct answer
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Answer:

Smallest surface area is of Cuboid B i.e 440 cm²

So, The company will choose cuboid B

Step-by-step explanation:

We need to find the surface area of all cuboids.

Surface Area of Cuboid A:

Length = 6

Breadth = 25

Height = 4

The formula used is: Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)

Putting values and finding surface area:

Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2((6 \times 25)+(25 \times 4)+(6 \times 4))\\Surface \ Area \ of \ Cuboid=2(150+100+24)\\Surface \ Area \ of \ Cuboid=2(274)\\Surface \ Area \ of \ Cuboid=548\: cm^2

So, Surface Area of Cuboid A = 548 cm²

Surface Area of Cuboid B:

Length = 10

Breadth = 6

Height = 10

The formula used is: Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)

Putting values and finding surface area:

Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2(10 \times 6)+(6 \times 10)+(10 \times 10))\\Surface \ Area \ of \ Cuboid=2(60+60+100)\\Surface \ Area \ of \ Cuboid=2(220)\\Surface \ Area \ of \ Cuboid=440\: cm^2

So, Surface Area of Cuboid B = 440 cm²

Surface Area of Cuboid C:

Length = 2

Breadth = 20

Height = 15

The formula used is: Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)

Putting values and finding surface area:

Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2((2 \times 20)+(20 \times 15)+(2 \times 15))\\Surface \ Area \ of \ Cuboid=2(40+300+30)\\Surface \ Area \ of \ Cuboid=2(370)\\Surface \ Area \ of \ Cuboid=740\: cm^2

So, Surface Area of Cuboid C = 740 cm²

So, We get:

Surface Area of Cuboid A = 548 cm²

Surface Area of Cuboid B = 440 cm²

Surface Area of Cuboid C = 740 cm²

The company wants to choose the design having smallest surface area.

So, smallest surface area is of Cuboid B i.e 440 cm²

So, The company will choose cuboid B

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