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Citrus2011 [14]
3 years ago
12

Mitchell is a big coffee fan, so he always takes care of coffee brewing at the office. Normally he uses 100 grams of Robusta cof

fee to prepare 10 cups of coffee. His friend brings him a packet of Arabica coffee and tells him that he should use 20% more than usual when brewing Arabica coffee. How many grams of coffee should he use to make a 15-cup pot of Arabica coffee?
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
7 0

he uses 100 grams for 10 cups

 20% more would be 100 *1.20 = 120 grams for 10 cups

15/10 = 1.5

120*1.5 = 180

he needs 180 grams for 15 cups.

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Check explanation below.

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Hello!

The objective of this experiment is to test if doctor Doom is controlling the neighbors' minds from his new Lair. To test this a random sample of 11 neighbors was taken and a "free will" test was administrated before the Villain's Lair was constructed and again after it was finished.

This experiment type where you have a single sample and the variable is measured "before" and "after" applying a treatment (in this case, that doctor Doom has moved into town) is a classic example of a paired sample test. You have two dependent variables, X₁: "Results of the free will test before Dr. Doom Lair is constructed" and X₂: "Results of the free will test after Dr. Doom Lair is constructed", with these variables you can establish a new variable, Xd, that I'll define as " X₁- X₂", and the objective of my hypothesis test will be to know if there is any change after the Lair is done, if there is, in fact, a change then the population mean of the difference will be nonzero, symbolically: μd ≠ 0

Using the data I've calculated the summary measures for Xd:

sample mean: Xd[bar]= 3.18

sample standard deviation: Sd= 5.44

The statistic hypothesis is:

H₀: μd = 0

H₁: μd ≠ 0

α: 0.05

(There is no signification level specified, so I've chosen the most common one)

Assuming that the variable difference, Xd, has a normal distribution, and with unknown population variance, the best statistic to use is the Students-t for paired samples:

t=  Xd[bar] - μd  ~t_{n-1}

Sd/√n

This test is two-tailed, so you will reject at low values of the statistic or at high values of it.

t_{n-1;\alpha/2 } = t_{10; 0.025} = -2.228

t_{n-1; 1-\alpha /2} = t_{10; 0.975} = 2.228

If t ≤ -2.228 or t ≥ 2.228 then you reject the null hypothesis.

If -2.228 < t < 2.228 then you don't reject the null hypothesis.

t= <u> Xd[bar] - μd  </u> =  <u> 3.18 - 0  </u> = 1.94

        Sd/√n             5.44/√11

Since the statistic value t= 1.94 then the decision is to not reject the null hypothesis.

So, with a significance level of 5% there is not enough evidence to reject the null hypothesis, this means that the population mean of the difference on the free will test results of the neighbors before and after the Villain's Lair was constructed is equal to cero. In other words, there is not enough evidence to conclude that Dr. Doom is controlling the neighbor's minds.

I hope it helps!

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