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lozanna [386]
3 years ago
7

Please help right away.

Mathematics
1 answer:
Travka [436]3 years ago
8 0

\sum\limits_{k=1}^{\infty}420\left(\dfrac{1}{6}\right)^{k-1}

The infinite geometric series is converges if |r| < 1.

We have r=1/6 < 1, therefore our infinite geometric series is converges.

The sum S of an infinite geometric series with |r| < 1 is given by the formula :

S=\dfrac{a_1}{1-r}

We have:

a_1=420\left(\dfrac{1}{6}\right)^{1-1}=420\left(\dfrac{1}{6}\right)^0=420\\\\r=\dfrac{1}{6}

substitute:

S=\dfrac{420}{1-\frac{1}{6}}=\dfrac{420}{\frac{5}{6}}=420\cdot\dfrac{6}{5}=84\cdot6=504

Answer: d. Converges, 504.

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Answer:

500

Step-by-step explanation:

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2 years ago
Please solve this, will rate 5 stars and mark as STAR!​
Nina [5.8K]

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Step-by-step explanation:

\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

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\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

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Once

\sqrt[6]{2}  \cdot \sqrt[6]{5} = \sqrt[6]{10}

We have

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5}

We can proceed considering the common base of exponentials

\sqrt[3]{2}  \cdot \sqrt[6]{2}  =  2^{\frac{1}{3}} \cdot  2^{\frac{1}{6} }  = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}

Therefore,

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2}  \cdot \sqrt[6]{5}

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Answer:

The money Keira spent on food is $31.

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Total money spent by Keira = $45

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2. Food

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For every egg you can make 4.5 cupcakes so you will need 8 small eggs because 8 times 4.5 equals 36
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Help! What's the slope?
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