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Anna [14]
3 years ago
15

Please, help with this now!

Mathematics
2 answers:
irga5000 [103]3 years ago
4 0
B would be equal to 3/6. 
Fractions with the same denominator are able to add together on the numerator. 
A is not correct because it is equal to 6/6, which is equivalent to 1. However, we are looking for 3/6, or 1/2 of a 1. 
C is not correct either because 3/3 is also equal to 1. 
D is also not correct because it is equal to 2. 3/3 = 1 
3/3 + 3/3 = 6/3 = 2 
77julia77 [94]3 years ago
4 0
The correct answer is B.
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One study on managers’ satisfaction with management tools reveals that 58% of all managers use self-directed work teams as a man
Marizza181 [45]

Answer:

6.94% probability that fewer than 35 use self-directed work teams as a management tool

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 70, p = 0.58

So

\mu = E(X) = np = 70*0.58 = 40.6

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{70*0.58*0.42} = 4.13

What is the probability that fewer than 35 use self-directed work teams as a management tool?

Using continuity correction, this is P(X < 35 - 0.5) = P(X < 34.5), which is the pvalue of Z when X = 34.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{34.5 - 40.6}{4.13}

Z = -1.48

Z = -1.48 has a pvalue of 0.0694.

6.94% probability that fewer than 35 use self-directed work teams as a management tool

4 0
3 years ago
Y’all I need the correct answer to this!! Please someone help
LuckyWell [14K]

Answer:

3/10 is larger

Step-by-step explanation:

3/10 is .30 while .25 is well .25

5 0
3 years ago
Read 2 more answers
ANSWER ASAP!! A movie club charges $10 per month, plus $1.50 per rental. Diego spends no more than $25 per month on movies. Desc
Dafna11 [192]

Answer:

The graph has a closed circle at 10

Step-by-step explanation:

Let

x ----> the number of rentals

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so

The inequality that represent this situation is

1.50x+10\leq 25

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x\leq 10

The number 10 is included in the solution

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The graph has a closed circle at 10

8 0
3 years ago
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Molly made a scaled copy of the following square. She used a scale factor greater than 1. What could be the side length of the s
riadik2000 [5.3K]

Answer:

D and E

Step-by-step explanation:

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3 years ago
A conjecture and the two-column proof used to prove the conjecture are shown.
slavikrds [6]

given: s is the midpoint of rt

definition of midpoint: rs st

given: st xy

transitive property of congruence: rs xy

8 0
3 years ago
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