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photoshop1234 [79]
3 years ago
9

How many different 4-digit numbers can be made from the digits 0, 1, 3, 5, and 7 if no digit is repeated in a number and zero ca

nnot be first number?
Mathematics
1 answer:
quester [9]3 years ago
6 0

Answer:

There are 96 ways different 4 digit numbers which can be made from these 5 digits.

Step-by-step explanation:

There are 5 different digits. The first one must be

1 3 5 or 7

So you can have 4 for the first one. Now the zero can be put into the mix.

4 * 4 * 3 * 2

96

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svetoff [14.1K]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
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\end{array}\\\\
--------------------\\\\

\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
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now, with that template in mind, let's see

\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}

so, just change C to +3, thus C/B is 3/1
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makvit [3.9K]

I hope it is helpful for you .....

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ankoles [38]

Answer:

Volume = 24\ ft^3

Step-by-step explanation:

Given [Missing from the question]

Length = 170cm\\ Width = 100cm\\ Height = 40cm

Required

Determine the volume

This is calculated as:

Volume = Length * Width * Height

Volume = 170cm * 100cm * 40cm

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Convert to cubic foot [Divide by 28317 ]

Volume = \frac{680000\ ft/^3}{28317}

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AB

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