C, x = +-7. Difference of squares
Width of the actual barrier = 1.2 miles
Width of the barrier in the blueprint = 2 inches
2 inch dimension of blueprint = 1.2 miles of original
So, 1 inch dimension of blueprint = 1.2/2 = 0.6 miles.
Since the length of the barrier in the blueprint = 9 inches,
length of the actual barrier = 9(0.6) = 5.4 miles.
Answer:
The cost of her old laptop would be $52.
Step-by-step explanation:
Answer:
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Step-by-step explanation: