All categories

3 years ago

How do you graph quadratic functions

Mathematics

2 answers:

NARA [144]3 years ago

8 0

Answer:

you can plug it into a graphing calcuator right? or no

Step-by-step explanation:

kaheart [24]3 years ago

6 0

Let's go:

First: You must find the function roots. Function roots are values of y or f(x) when x equals zero.

After this, you use some values of x for find values of y.

And finally, you make the grafic with values founded.

I hope I helped you.

You might be interested in

Can someone help out I’m really slow at this and don’t understand it please:)

myrzilka [38]

Answer:

2) 160

3) 320

Step-by-step explanation:

you want to find out the slope so use the formula

y₂-y₁/ x₂-x₁ and plug in the numbers

320-80=240

4-1=3

divide 240/3= 80

multiply 80 * (x) so if we try and find x=2 it would be 160

80 * 3 = 240

check your work by multiplying 80 and 4 (320) which is your y value! hope this helps!

7 0

3 years ago

HELP EMERGENCY!!!! (2.5 x 10-10) (7 x 10-5)<br> Express your answer in scientific notation.

dangina [55]

Answer:

$1.75$ × $10^{-15}$

I hope this helps!

8 0

3 years ago

Translate the verbal phrase into an algebraic expression. Simplify the expression.

adoni [48]

X(x+6)
hope that helps :)

7 0

3 years ago

Madelyn is knitting a scarf for a holiday gift. So far, it's 4.5 centimeters long. She plans to

olchik [2.2K]

In order to make the question true the length should be 45cm not 4.5 cm , Solving accordingly

Let nights be x
Rate of change=5cm

The equation is

y=45-5x

As 45 is base amount we used it as y intercect

7 0

2 years ago

Without using a calculator, match each expression to the correct point.

solniwko [45]

Answer:

The locations of each irrational number are the following:

$\sqrt{16}$ - Point $a$

$\sqrt{27}$ - Point $b$

$\sqrt{32}$ - Point $c$

Step-by-step explanation:

$\sqrt{16}$ is an irrational number that is also rational, since $4^{2} = 16$ . Then, $\sqrt{16}$ must be point $a$ .

Both $\sqrt{27}$ and $\sqrt{32}$ are greater than $\sqrt{25} = 5$ and less than $\sqrt{36} = 6$ . Then, both are between 5 and 6. Since $\sqrt{27} < \sqrt{32}$ , $\sqrt{27}$ must be point $b$ and $\sqrt{32}$ must be point $c$ .

3 0

3 years ago