Answer:
1) Kinetic energy of the truck 1 is 600,000 joules.
Kinetic energy of the truck 2 is 1,837,500 joules.
2 a)Potential energy of truck 1 is 646,800 Joules.
b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.
Step-by-step explanation:
Mass of the truck 1 and truck 2,m = 3000 kg
Velocity of the truck 1,
= = 20 m./s
Velocity of the truck 2,
= 35 m./s
1. Kinetic energy of the truck 1:![\frac{1}{2}mv_{1}^2=\frac{1}{2}\times 3000 kg\times (20 m/s)^=600,000 joules](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv_%7B1%7D%5E2%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%203000%20kg%5Ctimes%20%2820%20m%2Fs%29%5E%3D600%2C000%20joules)
Kinetic energy of the truck 2:![\frac{1}{2}mv_{2}^2=\frac{1}{2}\times 3000 kg\times (35 m/s)^=1,837,500 joules](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv_%7B2%7D%5E2%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%203000%20kg%5Ctimes%20%2835%20m%2Fs%29%5E%3D1%2C837%2C500%20joules)
2.a) Energy loose by the truck 1:
Initial height of the truck on the hill = 22 m
At that height potential energy will be maximum:
Potential energy of truck 1 at that height = ![mgh=3000\times 9.8 m/s^2\times 22 m=646,800 Joules](https://tex.z-dn.net/?f=mgh%3D3000%5Ctimes%209.8%20m%2Fs%5E2%5Ctimes%2022%20m%3D646%2C800%20Joules)
b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.