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ivolga24 [154]
3 years ago
15

Brian has one and 7/10 kilograms of black pepper he uses 7/8 of the pepper and split sit between seven pepper shakers how much p

epper will be in each shaker
Mathematics
1 answer:
zubka84 [21]3 years ago
8 0
<span>Each pepper shaker has 7/80 kilograms of pepper. First, determine how much black pepper Brian distributed to all the pepper shakers. Do this by multiplying 7/10 by 7/8. 7/10 * 7/8 = 49/80 Now divide 49/80 by 7 to get the amount of pepper in each shaker. Division is the same as multiplication by the reciprocal, so multiply by 1/7. So 49/80 * 1/7 = 49/560 = 7/80 So each pepper shaker has 7/80 kilograms of pepper.</span>
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What is the answer and how to solve it and give me the right answer
Keith_Richards [23]

Answer:

2/10 or in its simplest form 1/5

Step-by-step explanation:

there is 2 grey marbles so 2/10 (there is 10 marbles altogether)

so half of 2 is 1 and half of 10 is 5

so the answer is 1/5

7 0
2 years ago
Read 2 more answers
Help!
11111nata11111 [884]
(4/7) / (3/-8)...when dividing fractions, flip what u r dividing by, then multiply
4/7 * - 8/3 =
- 32/21 <===
3 0
2 years ago
PLS HELP TIMED QUESTION!!!
ser-zykov [4K]

Answer:

About 5043.58

Step-by-step explanation:

The standard form for an exponential decay after t time is:

\displaystyle f(t)=a(r)^{t/d}

Where a is the initial value, r is the rate decay, t is the time that has passed, and d is the amount of time it takes for 1 cycle.

The initial value is 9800. So a = 9800.

The quantity cuts in half. So, r = 1/2.

And it cuts in half every 6 days. For this question, we will convert this to hours. 6 days = 144 hours. So, we can let d = 144, where t will be in hours.

Therefore, our function is:

\displaystyle f(t)=9800\Big(\frac{1}{2}\Big)^{t/144}

Where t is the amount of time that has passed, in hours.

Then the quantity left after 138 hours will be:

\displaystyle f(138)=9800\Big(\frac{1}{2}\Big)^{138/144}\approx 5043.58

7 0
2 years ago
7.2÷(6.6×1.1+(2.2) to the second power-3.1)
Hoochie [10]

Answer:

0.98001931 is your answer : >

6 0
3 years ago
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Use the identity x3+y3+z3−3xyz=(x+y+z)(x2+y2+z2−xy−yz−zx) to determine the value of the sum of three integers given: the sum of
fenix001 [56]

ffn

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-(xy+yz+zx))

the sum of their squares is 110, So x^2+y^2 + z^2= 110

the sum of their cubes is 684, so  x^3+y^3 + z^3= 684

the product of the three integers is 210, so xyz= 210

the sum of any two products (xy+yz+zx) is 107

Now we plug in all the values in the identity

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-(xy+yz+zx))

684 - 3(210) = (x+y+z)(110-107)

684 - 630 = (x+y+z)(3)

54 = 3(x+y+z)

Divide by 3 on both sides

18 = x+y+z

the value of the sum of three integers is 18

3 0
3 years ago
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