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andrew11 [14]
3 years ago
6

Find the exact value by using a half-angle identity. sin 22.5degrees show your work. thanks!

Mathematics
1 answer:
Jobisdone [24]3 years ago
3 0
sin( \frac{ \alpha }{2})=\sqrt{ \frac{1-cos\alpha}{2} }\\\alpha=45^\circ\\ sin(22,5)=\sqrt{ \frac{1-cos45}{2} }\\ sin(22,5)=\sqrt{ \frac{1-\frac{\sqrt2}{2}}{2} }\\ sin(22,5)=\sqrt{ \frac{2-\sqrt2}{2}*\frac{1}{2} }\\sin(22,5)=\sqrt{ \frac{2-\sqrt2}{4} }
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Step-by-step explanation:

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3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%20%7B%7D%5E%7B2%7D%20%20%2B%2012x%20%2B%2036" id="TexFormula1" title="f(x)
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B

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We are given the function:

\displaystyle f(x) = x^2 + 12x + 36

And we want to determine the value of:

\displaystyle f^{-1}(225)

Let this value equal <em>a</em>. In other words:  

\displaystyle f^{-1}(225) = a

Then by the definition of inverse functions:

\displaystyle \text{If } f^{-1}(225) = a\text{, then } f(a) = 225

Hence:

\displaystyle f(a) =225 = (a)^2 + 12(a) + 36

Solve for <em>a: </em>

\displaystyle \begin{aligned} 225 &= a^2 + 12a + 36 \\ \\ a^2 + 12a -189 &= 0 \\ \\ (a + 21)(a-9) &= 0\end{aligned}

By the Zero Product Property:

\displaystyle a + 21 = 0 \text{ or } a - 9 = 0

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In conclusion, our answer is B.

3 0
3 years ago
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