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Scilla [17]
3 years ago
8

= x {}^{2} + 12x + 36" alt="f(x) = x {}^{2} + 12x + 36" align="absmiddle" class="latex-formula">
Determine the value of f^-1 (225) in this situation.
A. 21 days

B. 9 days

C. 6 days

D. 15 days​
Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0

Answer:

B

Step-by-step explanation:

We are given the function:

\displaystyle f(x) = x^2 + 12x + 36

And we want to determine the value of:

\displaystyle f^{-1}(225)

Let this value equal <em>a</em>. In other words:  

\displaystyle f^{-1}(225) = a

Then by the definition of inverse functions:

\displaystyle \text{If } f^{-1}(225) = a\text{, then } f(a) = 225

Hence:

\displaystyle f(a) =225 = (a)^2 + 12(a) + 36

Solve for <em>a: </em>

\displaystyle \begin{aligned} 225 &= a^2 + 12a + 36 \\ \\ a^2 + 12a -189 &= 0 \\ \\ (a + 21)(a-9) &= 0\end{aligned}

By the Zero Product Property:

\displaystyle a + 21 = 0 \text{ or } a - 9 = 0

Hence:

\displaystyle a = -21 \text{ or } a = 9

Thus, f(9) = 225. Consequently, f⁻¹(225) = 9.

In conclusion, our answer is B.

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Plsss help
Mkey [24]

Step-by-step explanation:

come in ! think a little bit by yourself !

when x = 1, what is f(x) ?

it is f(1) = 1² = 1

what is then g(x) ?

g(1) = 1/4 × f(1) = 1/4 × 1 = 1/4

when x = 2, what is f(x) ?

f(2) = 2² = 4

what is then g(x) ?

g(2) = 1/4 × f(2) = 1/4 × 4 = 1

and equally for x = -1 and -2.

a square function always delivers positive numbers. and so does the square function multiplied by a positive constant (like for g(x)).

the only graph, where the curve is always above the x-axis (only positive results), and where the functional value for x = 1 is much smaller than 1, and the functional value for x = 2 is actually 1, is graph D.

so, D is the right answer.

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