let
(hypotenuse ) c = 10 in
(perpendicular) a = 8 in
(base) b =?
By using Pythagoras theorem
c^2= a^2+b^2
(10)^2 = (8)^2 +(b)^2
100 = 64 +(b)^2
100- 64 = (b)^2
36 = (b)^2
√36 = b
6 = b
hence b= 6 in
Answer:
The second/below one is where point G in an orthocenter
Step-by-step explanation:
Answer:
a. y = (3/5)× x +1
Step-by-step explanation:
y= mx+c
m = (13-4)/(20-5) = 9/15 = 3/5
c= 1
so, y= mx+c becomes y= (3/5) × x +1
I'm pretty sure the answer is 259
