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frez [133]
3 years ago
11

A class of 30 introductory statistics students took a quiz worth 100 points. the standard deviation of the scores was 0. what mu

st be true about the students' scores?
Mathematics
2 answers:
bearhunter [10]3 years ago
8 0
This means that everybody answered the same number of items. This means that every data value is equal to the mean. This outcome permits us to say that the sample standard deviation of a data set is zero if and only if all of its values are same or identical.
Sloan [31]3 years ago
4 0

The answer is that all the scores are the same

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Find an equation for the line below <br> (Pls provide explanation)
leonid [27]

Answer:

y=-2/4x + (-4.5)

Step-by-step explanation:

so first we look for the slope which is rise/run.

start with the lower point and count up two.

the count to the left and you have -2/4, thats your slope.

then you chose one point, like (1,-5)

so either using point slope form y-y1=m(x-x1) or standard form y+mx+b

im going to use standard form

plug in your points like so:

y= -2/4x +b

-5= -2/4(1) +b

-5 = -1/2 + b

-5+ 1/2 = b

-4 1/2 =b

so y should equal

y=-2/4x + (-4.5)

im not sure but i hope this helps a bit

7 0
2 years ago
A classroom can accommodate less than 24 students.
Effectus [21]
The answer is c because it’s asking for less than so it goes left and the dot isn’t filled so it means less than
6 0
3 years ago
14 V = bdt. Solve the formula for de
snow_tiger [21]

Answer:

d=\dfrac{V}{bt}

Step-by-step explanation:

It is given that,

V = bdt i.e. V is equal to the product of b, d and t

We need to find the formula for d.

Dividing both sides of the given expression by bt

So,

\dfrac{V}{bt}=\dfrac{bdt}{bt}\\\\d=\dfrac{V}{bt},\ \text{bt in both denominator and numerator cancel out}

Hence, d=\dfrac{V}{bt} is the value of d.

5 0
3 years ago
3 classmates share 2 granola bars equally.
umka21 [38]

Answer:

3/2 or 1.5

Step-by-step explanation:

the answer would be 3/2 because the number of classmates divided by the number of granola bars equals how much each classmate would get in all.

5 0
3 years ago
A tank contains 1600 L of pure water. Solution that contains 0.04 kg of sugar per liter enters the tank at the rate 2 L/min, and
goldfiish [28.3K]

Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of

(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min

and flows out at a rate of

(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min

Then the net flow rate is governed by the differential equation

\dfrac{\mathrm dS(t)}{\mathrm dt}=\dfrac8{100}-\dfrac{S(t)}{800}

Solve for S(t):

\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{S(t)}{800}=\dfrac8{100}

e^{t/800}\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{e^{t/800}}{800}S(t)=\dfrac8{100}e^{t/800}

The left side is the derivative of a product:

\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}

Integrate both sides:

e^{t/800}S(t)=\displaystyle\frac8{100}\int e^{t/800}\,\mathrm dt

e^{t/800}S(t)=64e^{t/800}+C

S(t)=64+Ce^{-t/800}

There's no sugar in the water at the start, so (a) S(0) = 0, which gives

0=64+C\impleis C=-64

and so (b) the amount of sugar in the tank at time t is

S(t)=64\left(1-e^{-t/800}\right)

As t\to\infty, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.

7 0
4 years ago
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