Answer:
As you have written
Z Y = 3 X Y,
It means X, Y, Z are collinear points i.e they lie in the same line or line segment.
Locating points X, Y,Z on the line
Two possibilities are possible
1. First Z, then X and then Y on the line or line segment
→ Z X + Y X= Z Y
But Z Y = 3 X Y [ Given]
→ Z X + Y X = 3 X Y
→ Z X = 3 X Y - Y X
→ Z X = 2 X Y ⇒ which is not the result.
2. 2nd Possibility
First Z, then Y and then X on the line or line segment
→ Z X = Z Y + Y X
→ Z X= 3 X Y + Y X [Z Y=3 X Y→(given)]
→ Z X= 4 X Y , Which is the result.
Answer:
Step-by-step explanation:
<u>Eigenvalues of a Matrix</u>
Given a matrix A, the eigenvalues of A, called 
are scalars who comply with the relation:
Where I is the identity matrix
![I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=I%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
The matrix is given as
![A=\left[\begin{array}{cc}3&5\\8&0\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%265%5C%5C8%260%5Cend%7Barray%7D%5Cright%5D)
Set up the equation to solve
![det\left(\left[\begin{array}{cc}3&5\\8&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda \end{array}\right]\right)=0](https://tex.z-dn.net/?f=det%5Cleft%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%265%5C%5C8%260%5Cend%7Barray%7D%5Cright%5D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Clambda%260%5C%5C0%26%5Clambda%20%5Cend%7Barray%7D%5Cright%5D%5Cright%29%3D0)
Expanding the determinant
![det\left(\left[\begin{array}{cc}3-\lambda&5\\8&-\lambda\end{array}\right]\right)=0](https://tex.z-dn.net/?f=det%5Cleft%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3-%5Clambda%265%5C%5C8%26-%5Clambda%5Cend%7Barray%7D%5Cright%5D%5Cright%29%3D0)
Operating Rearranging
Factoring
Solving, we have the eigenvalues
Answer:
Step-by-step explanation:
but if
then since
so
or
Answer:
Amount she would have in 2 years at a simple interest of is
$5000 + ($5000 x 0.048 x 2) = $5480
Amount she would have in 2 years at a 4.1 % / year compounded semi- annually is :
$5000 x ( 1 +0.041/2)^4 = $5422.78
the first option yields a higher value in two years when compared with the second option. Thus, the first option is the best one to choose
Step-by-step explanation:
Future value with simple interest = principal + interest
Interest = principal x interest rate x time
0.048 x 5000 x 2 = 480
future value = $480 + 5000 = $5480
The formula for calculating future value with compounding:
FV = P (1 + r)^nm
FV = Future value
P = Present value
R = interest rate
m = number of compounding
N = number of years
5000 x ( 1 + 0.041 / 2)^(2 x 2) = $5422.78
5*3+2=17 it's A, 3 in this equation.
