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egoroff_w [7]
3 years ago
9

Mai wants to make an open top box by cutting out corners of a square piece of cardboard and folding up the sides. The cardboard

is 10 cm by 10 cm. The volume V(x) in cubic cm of the open top box is a function of the side length x in cm of the square cutouts

Mathematics
1 answer:
Bumek [7]3 years ago
5 0

Answer:

V(x)=(4x^{3}-40x^{2}+100x)\ cm^3

The domain for x is all real numbers greater than zero and less than 5 com

Step-by-step explanation:

<em><u>The question is</u></em>

What is the volume of the open top box as a function of the side length x in cm of the square cutouts?

see the attached figure to better understand the problem

Let

x -----> the side length in cm of the square cutouts

we know that

The volume of the open top box is

V=LWH

we have

L=(10-2x)\ cm

W=(10-2x)\ cm

H=x)\ cm

substitute

V(x)=(10-2x)(10-2x)x\\\\V(x)=(100-40x+4x^{2})x\\\\V(x)=(4x^{3}-40x^{2}+100x)\ cm^3

Find the domain for x

we know that

(10-2x) > 0\\10> 2x\\ 5 > x\\x < 5\ cm

so

The domain is the interval (0,5)

The domain is all real numbers greater than zero and less than 5 cm

therefore

The volume of the open top box as a function of the side length x in cm of the square cutouts is

V(x)=(4x^{3}-40x^{2}+100x)\ cm^3

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valina [46]

Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

Red = 5

White = 6

Black = 9

Required

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The total number of ball is:

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This is calculated as:

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So, we have:

P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1}  + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

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c

Step-by-step explanation:

Hey There!

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