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lutik1710 [3]
2 years ago
12

What is the value of y? y = 30 y = 50 y = 110 y = 130

Mathematics
1 answer:
____ [38]2 years ago
8 0

Answer:

The value of y is 50.

Step-by-step explanation:

It is 50 because it is the exact same as the first degree.

And at least give a picture of problem please so we can solve it easily!! hope you next time!!

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The perimeter of an equilateral triangle is 6n-15 . Write an expression to represent the length of each side.
jonny [76]

Answer:we know that all 3 sides are equal

so if side =a

then perimeter =3a

therefore

3a=6n-15

a=6n-15/3

a=2n-5

4 0
2 years ago
Help please i really need it asap
Varvara68 [4.7K]
The expression coud be re written:

12x²y/2xy + 6xy/2xy + 4x²/2xy . Simplify numerator & denominator whenever it is possible:

6x-3+2x/y
3 0
3 years ago
Complete the proof. What is reason #5?
Darya [45]

Statements

2. right triangle

3. PQ = OP

5. ∆ONP = ∆PQO

Reasons

1. Given

4. Given

5. SAS

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4 0
3 years ago
Use the integer tiles to evaluate the following expressions. 6 + 3 = 6 + (–4) = 6 + (–6) =
babunello [35]

Given:

The expressions are:

6+3

6+(-4)

6+(-6)

To find:

The value of given expression by using integer tiles.

Solution:

We have,

6+3

Here, both number are positive. When we add 6 and 3 positive integer tiles, we get 9 positive integer tiles as shown in the below figure. So,

6+3=9

Similarly,

6+(-4)

Here, 6 is positive and -4 is negative. It means we have 6 positive integer tiles and 4 negative integer tiles.

When we cancel the positive and negative integer tiles, we get 2 positive integer tiles as shown in the below figure. So,

6+(-4)=2

6+(-6)

Here, 6 is positive and -6 is negative. It means we have 6 positive integer tiles and 6 negative integer tiles.

When we cancel the positive and negative integer tiles, we get 0 integer tiles as shown in the below figure. So,

6+(-6)=0

Therefore, 6+3=9, 6+(-4)=2,6+(-6)=0.

8 0
3 years ago
In ΔOPQ, the measure of ∠Q=90°, OQ = 80, QP = 39, and PO = 89. What ratio represents the cosecant of ∠P?
Serjik [45]

Answer:

cos(O) = 39 / 89

Step-by-step explanation:

Given:

ΔOPQ, where

∠Q=90°

PO = 89

OQ = 39

QP = 80

cosine of ∠O?

cos(O) = Adjacent / Hypotenuse

cos(O) = 39 / 89

3 0
3 years ago
Read 2 more answers
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