Simplify.

Events A and B are mutually exclusive, with P(A) = 0.36 and P(B) = 0.05.

quester [9]

I think it is A 0.018

4 0

3 years ago

9

Kamila [148]

Hope this helps
1.$40
2.$42.80
3.$51.36

5 0

3 years ago

Please help with a, b, and c!!

padilas [110]

(a).
The product of two binomials is sometimes called FOIL.
It stands for ...

   the product of the First terms (3j x 3j)
plus
   the product of the Outside terms (3j x 5)
plus
   the product of the Inside terms (-5 x 3j)
plus
   the product of the Last terms (-5 x 5)

FOIL works for multiplying ANY two binomials (quantities with 2 terms).

Here's another tool that you can use for this particular problem (a).
It'll also be helpful when you get to part-c .

Notice that the terms are the same in both quantities ... 3j and 5 .
The only difference is they're added in the first one, and subtracted
in the other one.

Whenever you have

      (the sum of two things) x (the difference of the same things)

the product is going to be

   (the first thing)² minus (the second thing)² .

So in (a), that'll be (3j)² - (5)² = 9j² - 25 .

You could find the product with FOIL, or with this easier tool.
______________________________

(b).
This is the square of a binomial ... multiplying it by itself. So it's
another product of 2 binomials, that both happen to be the same:

(4h + 5) x (4h + 5) .

You can do the product with FOIL, or use another little tool:

The square of a binomial (4h + 5)² is ...

   the square of the first term    (4h)²
plus
   the square of the last term       (5)²
plus
   double the product of the terms 2 · (4h · 5)
________________________________

(c).
Use the tool I gave you in part-a . . . twice .

The product of the first 2 binomials is    (g² - 4) .

The product of the last 2 binomials is also (g² - 4) .

Now you can multiply these with FOIL,
or use the squaring tool I gave you in part-b .

5 0

3 years ago

Read 2 more answers

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

Marina86 [1]

Answer:

(a) 0.94

(b) 0.20

(c) 90.53%

Step-by-step explanation:

From a population (Bernoulli population), 90% of the bearings meet a thickness specification, let $p_1$ be the probability that a bearing meets the specification.

So, $p_1=0.9$

Sample size, $n_1=500$ , is large.

Let X represent the number of acceptable bearing.

Convert this to a normal distribution,

Mean: $\mu_1=n_1p_1=500\times0.9=450$

Variance: $\sigma_1^2=n_1p_1(1-p_1)=500\times0.9\times0.1=45$

$\Rightarrow \sigma_1 =\sqrt{45}=6.71$

(a) A shipment is acceptable if at least 440 of the 500 bearings meet the specification.

So, $X\geq 440.$

Here, 440 is included, so, by using the continuity correction, take x=439.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{339.5-450}{6.71}=-1.56$ .

So, the probability that a given shipment is acceptable is

$P(z\geq-1.56)=\int_{-1.56}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}}=0.94062$

Hence, the probability that a given shipment is acceptable is 0.94.

(b) We have the probability of acceptability of one shipment 0.94, which is same for each shipment, so here the number of shipments is a Binomial population.

Denote the probability od acceptance of a shipment by $p_2$ .