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goblinko [34]
3 years ago
13

A small cafe sells drip coffee for $0.95 per cup. On average, it costs the cafe $0.25 to make a cup of coffee(for grounds, hot w

ater, filters). The cafe also has a fixed daily cost of $200 (for rent, wages, utilities).
a) let R, C, and P be the cafe's daily revenue, costs, and profit, respectively, for selling x cups of coffee in a day. Find formulas for R, C, and P as functions of x. [hint: The revenue, R, is the total amount of money that the cafe brings in. The cost, C, includes the fixed daily cost as well as the cost for all x cups of coffee sold. P is the cafe's profit after costs have been accounted for.]
b) Plot P against x. For what x-values is the graph of P below the x-axis? Above the x-axis?
Mathematics
1 answer:
Katen [24]3 years ago
8 0
I think its b but i am not really sure
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2(x-5) + 3y + 12 - y
Arturiano [62]

Answer:

2(x+y+11)

Step-by-step explanation:

2(x+5)+3y+12−y

Use the distributive property to multiply 2 by x+5.

2x+10+3y+12−y

Add 10 and 12 to get 22.

2x+22+3y−y

Combine 3y and −y to get 2y.

2x+22+2y

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3 years ago
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Sherman hopes to get at least a 90 average on his science test. He has one more test before the end of the year. His past test s
aleksandr82 [10.1K]
(79 + 94 + 91 + 92 + x) / 5 > = 90
(356 + x) / 5 > = 90
356 + x > = 90 * 5
356 + x > = 450
x > = 450 - 356
x > = 94 <=== Sherman can get the lowest score at 94
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3 years ago
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If a football field is 100 yd long, how would you find its length in miles?
kozerog [31]

Answer:

If it is yards to miles, you divide. Precisely by 1760.

Therefore, if you were to divided 100 bye 1760, it would be around 0.0568182

Step-by-step explanation:

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The ratio of the weight of an object on planet earth to the weight of the same object on planet B is 100 to 3 if an elephant wei
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144 pounds

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100:3 = 4800:b

100/3=4800/b

100b=14400

b=144

Therefore, 144 pounds

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3 years ago
Preciso de ajudaa! Resolução também! - Considere as funções f e g tais que f(x)= x³+1 e g(x)= x-2 Determine: a)(fog)(0) b)(gof)(
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Answer:

(fog)(x) means that we have the function f(x) evaluated in the function g(x), or f(g(x)).

So, if f(x) = x^3 + 1 and g(x) = x - 2.

we have:

a) (fog)(0) = f(g(0)) = (0 - 2)^3 + 1 = -8 + 1 = -7

b) (gof)(0) = g(f(0)) = (0^3 + 1) - 2 = -1

c)  (fof)(1) = f(f(1)) = (1^3 + 1)^3 + 1 = 2^3 + 1 = 8 + 1 = 9

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4 years ago
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