So i know how to do this but.... im confusing my self >n< please help me
1 answer:
Answer:
see the attached graph
Step-by-step explanation:
When an equation is in <em>standard form</em> (or almost standard form), I like to put it into <em>intercept form</em> for graphing. Here, it is convenient to divide the equation by 2 to put it in standard form (coefficients mutually prime).
x +3y = -3
Now, it is convenient to divide by the constant on the right (-3) to put the equation into intercept form:
x/(-3) +y/(-1) = 1
The denominators are the x- and y-intercepts, respectively. Plot those, (-3, 0) and (0, -1), and draw the line through them.
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Point N(7, 4) is translated 5 units up.
And we have to find the coordinates of its image after this transformation.
Since the point translated up by 5 units, so the x coordinate remains same and we have to add 5 to y coordinate.
So the new coordinate after the transformation is
And that's the required coordinate after the given transformation .