Question

A certain amount of hydrogen peroxide was dissolved in 100. ml of water and then titrated with 1.68 m kmno4. what mass of h2o2 was dissolved if the titration required 13.3 ml of the kmno4 solution?

Answer 1

The solution for the problem is:

First, use the concentration of the volume of the thing you know to compute for the moles of that substance. Then, use the coefficient in the balanced equation to relay moles of that to moles of anything else in the chemical equation. Lastly, translate moles into mass by means of its molar mass, or into a concentration using the volume.

 

Applying what I have said earlier:

0.0133 L X 1.68 mol/L = 0.0223 mol KMnO4 X (1 mol H2O2 / 2 mol KMnO4) = 0.0112 mol H2O2 

Mass H2O2 = 0.0112 mol H2O2 X 34.0 g/mol = 0.380 grams H2O2