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blagie [28]
3 years ago
15

How many grams of butane can be burned by 1.42 moles of oxygen?

Chemistry
1 answer:
Mrrafil [7]3 years ago
6 0

Answer:

So the molar mass of C4,H10 is

58.12g mole -1

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If 5.2 moles of oxygen react, how many moles of nitrogen monoxide are produced? _______ Round to the nearest tenth, include unit
MArishka [77]

Answer:

10.4 moles

Explanation:

Given parameters:

Number of moles of oxygen = 5.2moles

Number of moles of nitrogen monoxide = ?

Solution:

To solve this problem, we need to work from the known to the unknown specie according to the reaction.

Oxygen gas is known and we can estimate the amount of mole of nitrogen monoxide;

         

Let us write the balanced reaction equation;

                N₂    +      O₂          →          2NO

  according to this reaction;

       1 mole of oxygen gas will produce 2 mole of NO

       5.2 moles of oxygen gas will produce  (5.2 x 2)moles  = 10.4moles

7 0
3 years ago
Read 2 more answers
Which of the following gases will diffuse the fastest at room temperature?
maw [93]

Answer:

I am pretty sure that it is A. H2.

Explanation:

Sorry if it's wrong.

4 0
3 years ago
Help plz and no link​
bagirrra123 [75]
Need more of a backstory to this?
7 0
3 years ago
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A(n) ____________________ is a compound that turns litmus blue and is often found in soaps and detergents.
ehidna [41]
B. base
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8 0
3 years ago
If 8.500 g CH is burned and the heat produced from the burning is added to 5691 g of water at 21 °C, what is the final
mojhsa [17]

The final temperature = 36 °C

<h3>Further explanation</h3>

The balanced combustion reaction for C₆H₆

2C₆H₆(l)+15O₂(g)⇒ 12CO₂(g)+6H₂O(l)  +6542 kJ

MW C₆H₆ : 78.11 g/mol

mol C₆H₆ :

\tt \dfrac{8.5}{78.11}=0.109

Heat released for 2 mol C₆H₆ =6542 kJ, so for 1 mol

\tt \dfrac{0.109}{2}\times 6542=356.539~kJ/mol

Heat transferred to water :

Q=m.c.ΔT

\tt 356.539=5.691~kg\times 4.18~kj/kg^oC\times (t_2-21)\\\\t_2-21=15\rightarrow t_2=36^oC

3 0
2 years ago
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