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Leni [432]
3 years ago
12

Which of these statements is correct? a. Particles in a suspension will settle out if left undisturbed. b. A solution is heterog

eneous. c. A colloidal system does not exhibit the Tyndall effect. d. The particles in a colloidal system are all the same size.
Chemistry
1 answer:
tatuchka [14]3 years ago
4 0

Blood. It is discrete cells in saline solutuion. The cells are free to move thru the plasma, or you wouldn't have blood flow, or oxygenation, and you would die. Blood is defined as liquid, not jello.


The other three are things not normally associated--water will fall from the sky as rain, for example, but is held in suspension in fog. Same with the salad oil in mayo. O.J. can be a suspension; easily separated by a filter, Or a colloid--depends if the pulp, if Any, is held in suspension or not. Usually, pulp will settle to the bottom, making that sample of Orange juice a suspension. At different temperatures, it acts differently. But, so does Fog. A colloid is something that normally shouldn't be as some of its molecules are too dense to normally "float" in suspension. Colloid means "glue".



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How many grams in a kilogram,how many quarts are in a pint and if how many ml of h20 = 1g
vodomira [7]

Answer:

1 g  +  10 g

Explanation:

5 0
3 years ago
Read 2 more answers
Draw a mechanism for this reaction. 5-hydroxypentanoic acid forms 2-oxanone in the presence of acid. draw all missing reactants
Licemer1 [7]

Answer: -

The first step involves protonation of the carbonyl oxygen.

After protonation, the Alcohol oxygen now attacks the carbon of the carbonyl.

Thus a six membered ring is formed with 5 carbon atoms and 1 oxygen atom. The 1st position carbon atom has 2 OH groups.

One of these gets again protonated.

This leaves as water. With the loss of the H+, there results a carbonyl at 1 position.

Thus 5-hydroxypentanoic acid forms a lactone or 2-oxanone in presence of acid.

3 0
3 years ago
What molarity of nitric acid (HNO3) was used if 2.00 L must be used to prepare 4.5 L of a 0.25 M HNO3 solution?
Ymorist [56]

The   molarity  of (HNO₃) that was used  if 2.00 L must  be used   to prepare 4.5 L  of a 0.25M HNO₃ solution is   0.563 M


 <u><em>calculation</em></u>

  This is calculated  usind  M₁V₁=M₂V₂  formula

where,

         M₁(  molarity ₁) = ?

         V₁( volume ₁) = 2.00 L

        M₁ (molarity ₂) = 0.25M

         V₂( volume₂) = 4.5 L

make M₁ the subject  of the formula by  diving both side of the formula  by V₁

   M₁  is therefore = M₂V₂/V₁

M₁ =[ (0.25 M  x 4.5 L) / 2.00 L ]  =0.563 M

5 0
3 years ago
A 53. 5 mL ample of an 5. 4 % (m / v) KBr olution i diluted with water o that the final volume i 205. 0 mL Expre your anwer to t
gogolik [260]

The concentration after dilution is 1.4%.

We are aware that concentration and volume are related to each other by the formula -

C_{1} V_{1} = C_{2} V_{2}, where we have initial concentration and volume on Left Hand Side and final concentration and volume on Right Hand Side.

Keep the values to calculate final concentration.

C_{2} = (53.5 × 5.4)/205.0

Performing multiplication on Right and Side

C_{2} = 288.9/205.0

Performing division on Right Hand Side

C_{2} = 1.4%

Hence, the final concentration is 1.4%.

Learn more about concentration -

brainly.com/question/17206790

#SPJ4

The complete question is -

A 53.5 mL sample of an 5.4 % (m/v) KBr solution is diluted with water so that the final volume is 205.0 mL.

Calculate the final concentration and express your answer to two significant figures and include the appropriate units.

3 0
1 year ago
PLEASE HELP I'LL GIVE YOU BRAINLIEST!!
In-s [12.5K]

Answer:

C

Explanation:

5 0
3 years ago
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