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Orlov [11]
3 years ago
13

Three times a number is the difference between four and that number

Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0
Convert it to an equation.

"Three times a number"
\sf 3n

"is"
=

"the difference between four and that number"
\sf 4-n

Put it all together:

\sf 3n=4-n

Solve for 'n', add 'n' to both sides:

\sf 4n=4

Divide 4 to both sides:

\boxed{\sf n=1}
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Which equation shows that the Pythagorean identity is true for 0=270 degrees. select the equation that is in the form sin^2 0+co
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Answer:

c. (-1)²+0²=1

hope it is helpful to you.

5 0
3 years ago
Derek's car has run out of gasoline. He walks 24 km west and then 10 km south looking for a gasoline station. If he is now h km
Juliette [100K]

Answer:

the value of h is √676km

Step-by-step explanation:

The computation of the value of h is shown below

Here we apply the Pythagoreus theorem

= 24^2 + 10^2

= 576 + 100

= √676

Hence, the value of h is √676km

We simply determine by using the Pythagoreus theorem

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2 years ago
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agasfer [191]
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7 0
3 years ago
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Write the equation of the circle with center (−1, −3) and (−7, −5) a point on the circle.
Pepsi [2]
So, we know the center is at -1, -3, hmmm what's the radius anyway?

well, the radius will be the distance from the center to any point on the circle, it just so happen that we know -7, -5 is on it, thus

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -1 &,& -3~) 
%  (c,d)
&&(~ -7 &,& -5~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
r=\sqrt{[-7-(-1)]^2+[-5-(-3)]^2}\implies r=\sqrt{(-7+1)^2+(-5+3)^2}
\\\\\\
r=\sqrt{36+4}\implies r=\sqrt{40}\\\\
-------------------------------

\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{-1}{ h},\stackrel{-3}{ k})\qquad \qquad 
radius=\stackrel{\sqrt{40}}{ r}
\\\\\\\
[x-(-1)]^2+[y-(-3)]^2=(\sqrt{40})^2\implies (x+1)^2+(y+3)^2=40
5 0
3 years ago
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