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ZanzabumX [31]
3 years ago
15

The local skating rink pays Mary a fixed rate per pupil plus a base amount to work as a skating instructor. She earns $90 for

Mathematics
1 answer:
baherus [9]3 years ago
5 0

Answer:The expressions for the payment made to Mary are,

        (Monday)      90 = 15m + b

        (Tuesday)     62 = 8m + b

where m and b are the fee per student and the base fee, respectively. Solving for m and b, the values are 4 and 30.

The equation that represents Mary's earning is

                                   y = 4x + 30

For 20 students,

                                   y = 4(20) + 30 = 110

For Lisa's earnings,

                                    y = 8x + 15

Substituting 20,

                                   y  =8(20) + 15 = 175

Thus, Lisa would earn more than Mary by $65.

Read more on Brainly.com - brainly.com/question/1560980#readmore

Step-by-step explanation:

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Dylan read his book for 2 2/3 hours and Faith read her's for 1 1/5.How much longer did did Dylan read then Faith?
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Use your understanding of the unit circle and trigonometric functions to find the values requested.
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Answer:

a) For this case we can use the fact that sin (\pi/3) = \frac{\sqrt{3}}{2}

And for this case since we ar einterested on -\frac{\pi}{3} and we know that the if we are below the y axis the sine would be negative then:

sin (-\pi/3) = -\frac{\sqrt{3}}{2}

b) From definition we can use the fact that tan x= \frac{sin x}{cos x} and we got this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}

We can use the notabl angle \pi/4 and we know that :

sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}

Then we know that 5\pi/4 correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1

Step-by-step explanation:

For this case we can use the notable angls given on the picture attached.

Part a

For this case we can use the fact that sin (\pi/3) = \frac{\sqrt{3}}{2}

And for this case since we ar einterested on -\frac{\pi}{3} and we know that the if we are below the y axis the sine would be negative then:

sin (-\pi/3) = -\frac{\sqrt{3}}{2}

Part b

From definition we can use the fact that tan x= \frac{sin x}{cos x} and we got this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}

We can use the notabl angle \pi/4 and we know that :

sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}

Then we know that 5\pi/4 correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1

6 0
3 years ago
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