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ZanzabumX [31]
3 years ago
14

Plz help it would really help me a lot

Mathematics
1 answer:
ruslelena [56]3 years ago
4 0

Answer:

A. 9 in

Step-by-step explanation:

The diameter of the circle is 18 in. The radius is half the diameter of the circle.

d= 18 in

r= 18/2

= 9 in

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Suppose we want to choose 5 colors, without replacement, from 8 distinct colors.1. If the order is relevant, how many can be don
Charra [1.4K]

(1) From the information given, if we want to choose 5 colors from 8 distinct colors and the order in which the selection is made is relevant, then what we have is a permutation.

The formula is given as;

nP_r=\frac{n!}{(n-r)!}

This formula means we need to select/arrange r items out of a total of n items and the anwer derived would be the total number of arrangements possible.

Therefore, we would have;

\begin{gathered} nP_r\Rightarrow_8P_5 \\ _8P_5=\frac{8!}{(8-5)!}\Rightarrow\frac{8!}{3!} \\ _8P_5=\frac{8\times7\times6\times\ldots1}{3\times2\times1}\Rightarrow\frac{40320}{6} \\ _8P_5=6720 \end{gathered}

Therefore, if the order is relevant, this selection can be done in 6,720 ways.

(2) If the order is NOT relevant, then what we need to calculate is a combination and the formula is;

_nC_r=\frac{n!}{(n-r)!r!}

The formula can now be applied as follows;

\begin{gathered} _nC_r\Rightarrow_8C_5 \\ _8C_5=\frac{8!}{(8-5)!\times5!} \\ _8C_5=\frac{8!}{3!\times5!}\Rightarrow\frac{8\times7\times6\times\ldots1}{(3\times2\times1)\times(5\times4\times\ldots1)} \\ _8C_5=\frac{40320}{6\times120} \\ _8C_5=56 \end{gathered}

If the order is not relevant, then the selection can be done in 56 ways.

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\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad &#10;\begin{array}{llll}&#10;\textit{plug in the values for }&#10;\begin{cases}&#10;y_1=4\\&#10;x_1=0\\&#10;m=\boxed{?}&#10;\end{cases}\\&#10;\textit{and solve for "y"}&#10;\end{array}\\&#10;\left. \qquad   \right. \uparrow\\&#10;\textit{point-slope form}

once you get the slope and solve for "y", that'd be the equation of the line.
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