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Bezzdna [24]
3 years ago
13

10% of what is 80,000?

Mathematics
2 answers:
Nataly [62]3 years ago
6 0

Answer:

let the no be x ..then,

10% of x =80,000

10x=80,000*100

x=80,00,000/10

x=8,00,000

hence 10%of 8,00,000 is 80,000

Morgarella [4.7K]3 years ago
4 0

= 8000

Step-by-step explanation:

<h2><em>Percentage solution with steps:</em></h2>

<em>Percentage solution with steps:Step 1: Our output value is 80000.</em>

<em>Percentage solution with steps:Step 1: Our output value is 80000.Step 2: We represent the unknown value with $x$.</em>

<em>Percentage solution with steps:Step 1: Our output value is 80000.Step 2: We represent the unknown value with $x$.Step 3: From step 1 above,$80000=100\%$.</em>

<em>Percentage solution with steps:Step 1: Our output value is 80000.Step 2: We represent the unknown value with $x$.Step 3: From step 1 above,$80000=100\%$.Step 4: Similarly, $x=10\%$.</em>

<em>Percentage solution with steps:Step 1: Our output value is 80000.Step 2: We represent the unknown value with $x$.Step 3: From step 1 above,$80000=100\%$.Step 4: Similarly, $x=10\%$.Step 5: This results in a pair of simple equations:</em>

<em>8</em><em>0</em><em>0</em><em>0</em><em>0</em><em> </em><em>=</em><em> </em><em>100%</em>

<em>x </em><em>=</em><em> </em><em>1</em><em>0</em><em>%</em><em> </em><em>(</em><em>2</em><em>)</em>

<em>Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both</em>

<em>Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of bothequations have the same unit (%); we </em><em>have</em>

<em>\frac{8000}{x}  \:  \:  \:  \:  \:  \:  \:  \frac{100\%}{1\%}</em>

<em>Step 7: Again, the reciprocal of both sides </em><em>gives</em>

<em>\frac{x}{8000 }  \:  \:   =  \: \:  \frac{10}{100}</em>

<em>= x = 8000</em>

<em>Therefore, 10</em><em>%</em><em> </em><em> </em><em>of </em><em>8</em><em>0</em><em>0</em><em>0</em><em> </em><em>is </em><em>8</em><em>0</em><em>0</em>

<em>hope </em><em>it</em><em> helps</em>

<em>#</em><em>c</em><em>a</em><em>r</em><em>r</em><em>y</em><em> </em><em>on</em><em> learning</em>

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