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kondaur [170]
3 years ago
11

Anyone know how to do parts of complex numbers

Mathematics
1 answer:
Agata [3.3K]3 years ago
6 0

Answer:

Re = 6.2

Im = 37

Step-by-step explanation:

Re is the Real Axis which is the real number in the equation (6.2).

Im is the Imaginary Axis which is the imaginary number in the equation (37)

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Step-by-step explanation:

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3 years ago
find the value of "a" and "b" for which the limit exists both as x approaches 1 and as x approaches 2:
lbvjy [14]

Answer:

a = 4

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Step-by-step explanation:

If the given function is continuous at x = 1

\lim_{x \to 1^{-}} f(x)=(x+1)

                     =2

\lim_{x \to 1^{+}} f(x)=ax+b

                     =a+b

\lim_{x \to 1} f(x)=ax+b

                   =a+b

And for the continuity of the function at x = 1,

\lim_{x \to 1^{-}} f(x)=\lim_{x \to 1^{+}} f(x)=\lim_{x \to 1} f(x)

Therefore, (a + b) = 2 -------(1)

If the function 'f' is continuous at x = 2,

\lim_{x \to 2^{-}} f(x)=ax+b

                     =2a+b

\lim_{x \to 2^{+}} f(x)=3x

                     =6

\lim_{x \to 2} f(x)=3x

                   =6

Therefore, \lim_{x \to 2^{-}} f(x)=\lim_{x \to 2^{+}} f(x)=\lim_{x \to 2} f(x)

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Subtract equation (1) from (2),

(2a + b) - (a + b) = 6 - 2

a = 4

From equation (1),

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3 0
3 years ago
Find the value of x .Find the measurements of
Nastasia [14]

Answer:

17

Step-by-step explanation:

42+x=5x

-5        - 5

=17

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3 years ago
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