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shusha [124]
3 years ago
13

Does 8b−10+b+3b+2=7+2b+10b−18−3 have a solution

Mathematics
1 answer:
just olya [345]3 years ago
4 0

Answer:

No.

Step-by-step explanation:

If we combine all like terms first on the left, then the right-

We will have a solution of

-8+12b=12b-14

This is not true, therefore, 8b−10+b+3b+2=7+2b+10b−18−3 does not have a solution.

(DM or comment for further explanation)

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Answer:

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Answer:

   (\frac{8^4}{10^4} )^{-\frac{1}{4} }  = \frac{5}{4}

Step-by-step explanation:

<u><em>Explanation</em></u>

Given  

       (\frac{8^4}{10^4} )^{-\frac{1}{4} }

By using algebra formulas

  (\frac{a}{b} )^{m} = \frac{a^m}{b^n}

(\frac{8^4}{10^4} )^{-\frac{1}{4} } = \frac{(8^{4})^{\frac{-1}{4} }  }{(10^{4} )^{\frac{-1}{4} } }

(a^{m} )^{n} = a^{mn}

\frac{(8^{4})^{\frac{-1}{4} }  }{(10^{4} )^{\frac{-1}{4} } } = \frac{8^{4X\frac{-1}{4} } }{10^{4 X\frac{-1}{4} } }

          = \frac{8^{-1} }{10^{-1} }

           = \frac{10}{8} \\= \frac{5}{4}

<u><em>Final answer:-</em></u>

 (\frac{8^4}{10^4} )^{-\frac{1}{4} }  = \frac{5}{4}

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