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prohojiy [21]
4 years ago
11

Math hw..................

Mathematics
1 answer:
Murrr4er [49]4 years ago
5 0
Arc AB = 63 * 2 = 126 degrees
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Can somebody please help me with c? Thanks.
Ilia_Sergeevich [38]

Answer:

1300

Step-by-step explanation:

2600 x 0.5= 1300

8 0
4 years ago
At what elevation does the atomosphere become too thin to breath
prohojiy [21]
At around 20'000ft. and higher.
4 0
3 years ago
9.
Masja [62]

Answer: The Answer is D.

Step-by-step explanation: IT is D because a FUNCTION DOES NOT suppose to hit more than 1 point. You can also use the vertical line test meaning take a pencil or pen hold it up and down and drag it across you screen or paper, and if it hits more than 1 point it is NOT a FUNCTION. Plus rate the Brainlest

8 0
4 years ago
Q # 17. please help me with this
vredina [299]
Hi there!

Dimensions of rectangular room :-

• Length = 109 inches
• Breadth = 103 inches

Dimensions of square tiles :-

• Each side = 3 inches

It's known :-

No. of tiles = Area of rectangular room / Area of tile

No. of tiles = \dfrac {109 × 103}{3}

No. of tiles = \dfrac {11227}{9}

No. of tiles = 1,247

Hence,
Th' number of tiles required for the job is 1,247

~ Hope it helps!
3 0
3 years ago
Find the areas of the sectors formed by ∠DFE. Round your answers to the nearest hundredth.
bija089 [108]

Answer:

Area of the sector in red = 177.87 cm²

Area of the sector in blue = 437. cm²

Step-by-step explanation:

Area of the sector = \frac{\theta}{360}(\pi )(r)^2

Area of the sector shaded in blue = \frac{256}{360}(\pi )(14)^2

                                                        = 437.87 cm²

Central angle formed by sector shaded in red = 360 - 256 = 104°

Area of the sector shaded in red = \frac{104}{360}(\pi )(14)^2

                                                      = 177.884

                                                      ≈ 177.88 cm²

Therefore, area of the sector shaded in red = 177.87 cm² and area of the sector in blue = 437.88 cm²

6 0
3 years ago
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