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Nesterboy [21]
3 years ago
13

Round to the nearest hundredth 7.381

Mathematics
2 answers:
Soloha48 [4]3 years ago
6 0

Answer:

7.39

Step-by-step explanation:

emmainna [20.7K]3 years ago
5 0
7.39 is the answer .
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Given that 2(-x + 4)=3 prove that x=5/2
user100 [1]

Answer:

x = 5/2

Step-by-step explanation:

So firstly, you want to distribute. It'll make your life much easier.

-2x + 8 = 3

-2x = -5 (subtracting 8 from both sides)

x = 5/2 (dividing both sides by -2 to obtain x)

Hope this helps :)

7 0
3 years ago
-4|x-11|=-16 solve for x in the equation
BigorU [14]

Answer:

x = 7 and 15

Step-by-step explanation:

Divide both sides by -4...

| x - 11 | = 4

because

| -4 | = 4 and

| 4 | = 4

x - 11 = -4 and x - 11 = 4

solve for x in both equations.

x = 7 and x = 15

5 0
4 years ago
Which ordered pairs make the equation true?
Nata [24]
(-4,-2)
You just plug in the numbers from the ordered pair, into your equation. Remember, the formula for ordered pairs are (x,y). :)
6 0
3 years ago
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The number of students at valley view middle school increased by 10%, To 770 total students were endrolled at valley view middle
alexgriva [62]
Before the increase, there were 693 students
5 0
3 years ago
Use long or synthetic division to find the following quotients <br>(x^3+2x^2!22x-45)÷(x+5) ​
svetoff [14.1K]

Answer:

\boxed{\textsf{ The quotient is $\sf x^2-3x-7$ and the remainder is (-10).}}

Step-by-step explanation:

Here we will be using long division method to find the quotient . Here we need to divide (x³+2x²-22x-45) and (x+5) . So lets divide .

x+5) x³+2x²-22x-45 ( x² -3x -7

x³ + 5x²

- -

______________

- 3x²-22x -45

-3x² -15x

+ +

______________

-7x -45

-7x -35

______________

-10

<u>Quotient</u><u> </u>= x² -3x -7

<u>Remainder </u>= (-10)

<h3><u>★</u><u>Hence </u><u>the</u><u> </u><u>quotient</u><u> </u><u>is </u><u>x²</u><u> </u><u>-3x </u><u>-</u><u>7</u><u> </u><u>and </u><u>the</u><u> </u><u>remainder</u><u> </u><u>is </u><u>(</u><u>-</u><u>1</u><u>0</u><u>)</u><u> </u><u>.</u></h3>
7 0
3 years ago
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