2 years ago

Write a quadratic equation in the form x² + bx+c=0 that has the following

Mathematics

1 answer:

vfiekz [6]2 years ago

7 0

Answer:

x^2-6x+5

Step-by-step explanation:

To have roots at x=5 and x=1 you need to write is as follows

(x-5)(x-1)

you then need to multiply these two and get

x^2-6x+5

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3y + 8 = ½ y + 28 Find y

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$\text{Hi there! :]}$

$\large\boxed{y = 8}$

$3y + 8 = 1/2y + 28\\\\\text{Subtract 8 from both sides:}\\\\3y + 8 - 8 = 1/2y + 28 - 8\\\\3y = 1/2y + 20\\\\\text{Subtract 1/2y from both sides:}\\\\3y - 1/2y = 1/2y - 1/2y+ 20\\ \\\text{Convert 3y to 6/2y to make subtracting easier:}\\5/2y = 20\\\\\text{Divide both sides by 5/2 (Multiply by reciprocal, or 2/5):}\\\\\\5/2y * 2/5 = 20 * 2/ 5\\\\y = 8$

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I think it would have to be a problem with a negative number plus and positive number...

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The coordinates of the vertices of quadrilateral ABCD are A(-5, 1), B(-2,5), C(5, 3),

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To calculate a slope, we need to apply: $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Applying formula to each slope:

$m_{AB}=\frac{5-1}{-2-(-5)} = \frac{4}{3} \\m_{BC}=\frac{3-5}{5-(-2)} =\frac{-2}{7}\\m_{CD}=\frac{-1-3}{2-5}=\frac{-4}{-3} =\frac{4}{3}$

So, as you can see, there are equal pair of slopes, meaning that they are parallels, which<em> demonstrate that it's actually a quadrilateral figure.</em>

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