You should draw a picture to visualize the problem easier.
The circumference of inner circle = 44 ft
That means the radius of the inner circle:
2*pi*r = 44
r = 44/(2pi) = 22/pi
Using the picture you hopefully drew, we see that the radius of the outer circle:
22/pi + 2
To figure out the circumference of the outer circle:
2pi*(22/pi + 2) = 44 + 4pi
So how much bigger is the the circumference of the outer circle than the inner circle?
44 + 4pi - 44 = 4pi
It is 4pi bigger or 4 * (3.14) = 12.56 feet
Answer:
it‘s about
32.08 ft (if its not an answer choice try 32 or anywhere near that number)
Step-by-step explanation:
SO this is a simple example of triangles
We would need to find the heigh of the flagpole which is the leg of the triangle
The other side (14ft) is the 2nd leg of the triangle
And we know the hypotenuse is 35 ft
So we put that in Pythagorean Theroux and solve for the first missing leg
a^2+14^2=35^2
a^2+196=1225
a^2=1029
√1029 is about 32.08
So its about 32.08
0.008 i think this is the answer
Don’t know the answer you did put nothing
