Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
Answer:
The total surface area = 582 ft²
Step-by-step explanation:
To find the surface area of it count the number of faces at first
The figure has 8 faces each 2 are equal
1- Two faces with dimensions 4 ft and 15 ft ( base and shaded face)
2- Two faces with dimensions 9 ft and 4 ft
3- Two faces with dimensions 4 ft and 6 ft
4- Two faces with dimensions 15 ft , 9 ft and 6 ft
Area of (1-) = 2(4 × 15) = 120 ft²
Area of (2-) = 2(4 × 9) = 72 ft²
Area of (3-) = 2(4 × 6) = 48 ft²
Area of (4-) = 2[(9 × 9) + (6 × 15)] = 2[81 + 90] = 2 × 171 = 342 ft²
∴ The total surface area = 120 + 72 + 48 + 342 = 582 ft²
Part A
We have

. To solve for the x-intercept, we set f(x) equal to 0. That is

Take the square root of both sides,
The x-intercept is (-2,0).
To solve for the y-intercept, we set x=0. That is
The y-intercept is (0, 8)
The coordinates of the optimum point are actually the vertex which can be easily seen from the vertex form equation given above. The minimum point is
(-3, -1).
Part B.
We have

.
Factor out -2

Complete the square

Simplify

Part C
We have

.
The maximum height is 12.25 feet after 0.875 seconds from the time of the jump. The dolphin will be back in the water after 1.75 seconds. The graph of the jump is shown in the photo.
Answer:
5.24 in
Step-by-step explanation:
The arc length is calculated as
arc = circumference × fraction of circle
= 2πr × 
= 2π × 5 × 
=
≈ 5.24 in (2 dec. places )
Answer:
The triangle does not exist because sin(A)/a can not be equal to sin(B)/b
Step-by-step explanation:
we know that
step 1
Find the measure of angle B
Applying the law of sines

we have




substitute




Remember that the value of sine can not be greater than 1
therefore
The triangle does not exist because sin(A)/a can not be equal to sin(B)/b