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Phantasy [73]
2 years ago
7

The radius of a clock face is 8.5 cm.what is the area of a clock face?approximate pi as 3.14.

Mathematics
1 answer:
Alex73 [517]2 years ago
6 0
The answer should be 712.3
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1000000000000 x 21392938402840
aivan3 [116]

Answer:

2.1392938e+25Step-by-step explanation: you just times it so u get this answer

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Simplify. (3x^-2 y^4)^-3​
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Name a career in which one would have to use the phythagorean theorem.Give an example of when and how it would be used.Please wr
DanielleElmas [232]

Answer:

The careers that use Pythagoras theorem are mentioned below.

Step-by-step explanation:

The Pythagoras theorem states that the sum of squares of the two sides of right angled triangle is equal to the square of the length of the hypotenuse.

Let a, b and c be the sides of a right triangle where c is the length of the hypotenuse.Then

a^{2}+b^{2}=c^{2}

Pythagoras theorem is used in daily life situations.

A surveyor looks through a telescope toward a measuring stick a fixed distance away, so that the telescope's line of sight and the measuring stick form a right angle.

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8 0
3 years ago
What does mean mean please
Nady [450]
The mean is the average of a set of numbers, to find the mean, add all the numbers, then divide by the amount of numbers. 
8 0
3 years ago
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What is the diameter of the cylinder
vfiekz [6]
  • Diameter of cylinder is <u>1</u><u>4</u><u> </u><u>units.</u>
<h3><u>Explamation </u><u>:</u></h3>

<em><u>Given </u></em><em><u>:</u></em><em><u>-</u></em>

  • Volume of cylinder = 245π cubic units
  • Height of cylinder = 5 units

<em><u>To </u></em><em><u>Find </u></em><em><u>:</u></em><em><u>-</u></em>

  • Diameter of cylinder?

<em><u>Solution </u></em><em><u>:</u></em><em><u>-</u></em>

<em>Firstly </em><em>lets </em><em>calculate </em><em>radius </em><em>of </em><em>cylinder </em><em>by </em><em>using </em><em>formula </em><em>of </em><em>volume </em><em>of </em><em>cylinder,</em><em> </em><em>as </em><em>we </em><em>know </em><em>that;</em>

  • Volume of cylinder = πr²h

<em>Putting </em><em>all </em><em>values </em><em>we </em><em>get;</em>

➸ 245π = π × r² × 5

<em>By </em><em>cutting </em><em>'π' </em><em>with </em><em>'π' </em><em>we </em><em>get;</em>

➸ 245 = r² × 5

➸ 245/5 = r²

➸ 49 = r²

➸ √(49) = r²

➸ √(<u>7</u><u> </u><u>×</u><u> </u><u>7</u><u>)</u> = r²

➸ 7 = r

➸ r = 7 units

  • <u>Hence,</u><u> </u><u>radius </u><u>of </u><u>cylinder </u><u>is </u><u>7</u><u> </u><u>units.</u>

<em>Now </em><em>lets </em><em>calculate </em><em>its </em><em>diameter,</em><em> </em><em>as </em><em>we </em><em>know </em><em>that;</em>

  • Diameter = Radius × 2

<em>Putting </em><em>all </em><em>values </em><em>we </em><em>get;</em>

➸ Diameter = 7 × 2

➸ Diameter = 14 units

  • <u>Hence,</u><u> </u><u>diameter </u><u>of </u><u>cylinder </u><u>is </u><u>1</u><u>4</u><u> </u><u>units.</u>

5 0
2 years ago
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