Step-by-step explanation:
By inscribed angle theorem:
![m\angle ABC = \frac{1}{2} \times m\overset{\frown} {AC} \\\\\therefore \:m\angle ABC = \frac{1}{2} \times 50°\\\\\huge\purple {\boxed {\therefore \:m\angle ABC = 25°}}](https://tex.z-dn.net/?f=%20m%5Cangle%20ABC%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20m%5Coverset%7B%5Cfrown%7D%20%7BAC%7D%20%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%5Ctherefore%20%5C%3Am%5Cangle%20ABC%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%2050%C2%B0%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%5Chuge%5Cpurple%20%7B%5Cboxed%20%7B%5Ctherefore%20%5C%3Am%5Cangle%20ABC%20%3D%2025%C2%B0%7D%7D%20)
9 is the GCF of 18 and 36
Answer:
C.
Step-by-step explanation:
PEMDAS
-6 x 12p = -72p
-6 x -8n = 48n
48n - 47n = n
From the diagram, 6y = 90 [right angle]
y = 90/6 = 15
Also, 5y + 3x + 6y + 90 = 360 [sum of interior angle of a quadrilateral is 360]
5(15) + 3x + 6(15) + 90 = 360
75 + 3x + 90 + 90 = 360
3x = 360 - 255 = 105
x = 105/3 = 35
Therefore, x + y = 35 + 15 = 50.
Answer:
B. Similar squares
Step-by-step explanation:
The cross sections parallel to the base of a square pyramid, will form a square which will be similar to the base of the pyramid.
Also, if we consider a rectangular pyramid, the cross sections parallel to the base of the rectangular pyramid, will form a rectangle which will be similar to the base of the pyramid.
Thus, the paralel cross section to the base of any pyramid will form a similar shape of its base.