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QveST [7]
2 years ago
12

What is the equation of the axis of symmetry of the graph of y + 3x – 6 = –3(x – 2)2 + 4?

Mathematics
1 answer:
never [62]2 years ago
4 0
Axis of symmetry = -b/2a
y + 3x - 6 = -3(x-2)² + 4
y + 3x - 6 = -3 ( x²-4x+4) + 4
y + 3x - 6 = -3x² + 12x -12 + 4
y + 3x - 6 = -3x² + 12x -8
y = -3x² + 12x - 3x -8 + 6
y = -3x² + 9x -2
(a=-3, b=9, c=-2)
Axis of symmetry = -b/2a =  -9/2(-3) = -9 / -6 = -3 / -2 = 3/2
Hence, option A) x=3/2 is the correct answer. 
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This is the one and i know its probably super easy but i dont know
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Step-by-step explanation:

this one is a "thousand times" more complex than the inequality question to put there.

still easy, yes, for an experienced person, but here it is clear you need to understand lines, coordination grids, and overall deal with 2 variables (here : x and y) and therefore 2 dimensions.

the general line function is typically presented as

y = ax + b

a is the slope. that is the ratio of "y coordinate change / x coordinate change" when going from one point on the line to another.

and b is the y-intercept (the y value when x = 0), giving us the information about the point, where the line crosses the y-axis.

and so, look for yourself, which of the 4 equations has a b of +3 ?

y = 3x no, b = 0

y = x + 3 yes, b = 3, this is correct

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3 0
2 years ago
A factory produces some batteries daily. 7/8 of the batteries are packaged immediately. 2/3 of the
frozen [14]

Answer:

\[\frac{1}{24}\]

Step-by-step explanation:

Let the total number of batteries produced daily be represented by x.

7/8 of the batteries are packaged immediately.

So the total number of packaged batteries = \[\frac{7x}{8}\]

Remaining batteries = \[x-\frac{7x}{8}\]

= \[\frac{x}{8}\]

Two third of the remaining batteries are sent to charity.

So the total number of batteries sent to charity= \[\frac{2}{3} * \frac{x}{8}\]

= \[\frac{x}{12}\]

Remaining batteries are faulty.

So the total number of faulty batteries = \[\frac{x}{8} - \frac{x}{12}\]

= \[\frac{3x - 2x}{24}\]

= \[\frac{x}{24}\]

So the faction of batteries which are faulty =

= \[\frac{x}{24} \div x\]

= \[\frac{1}{24}\]

3 0
3 years ago
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shtirl [24]
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jekas [21]
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3 years ago
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bija089 [108]

Answer:

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Step-by-step explanation:

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A=6^{2} +2(6)\sqrt{\frac{6^{2} }{4} } +8^{2}

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3 years ago
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