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irakobra [83]
3 years ago
13

I am greater than 4 tens and less than 5 tens I have 9 ones what number am I?

Mathematics
1 answer:
dimaraw [331]3 years ago
5 0
x\ \in(40;50)\ \ \ and\ \ \ x=10p+9,\ \ \ p\in I+\\\\x=49\\\\Ans.\ The\ number\ is\ 49
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Help ASAP!!!! Thanks
Tema [17]

Answer:

No DB is not a perpendicular bisector of AC

Step-by-step explanation:

This is because as AC is a straight line it's angle degree is 180 which when bisected by DB becomes,

180 ÷ 2 = 90

On both the angles i.e <BDC = <NDA = 90°

To make it a perpendicular bisector but

<BDC is not equal to <NDA is not equal to 90°.

Hence, DB is not a perpendicular bisector of line AC.

8 0
3 years ago
Draw the image of the rotation of quadrilateral SORT by 270° about the origin​
cestrela7 [59]

Answer:

70

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A game is played with a spinner on a circle, like the minute hand on a clock. The circle is marked evenly from 0 to 100, so, for
zheka24 [161]

Answer:

The probability is 1/2

Step-by-step explanation:

The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.

When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.

As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

W = \frac{X - \mu}{\sigma} = \frac{X - 50}{8.333} \simeq N(0,1)

The values of the cummulative distribution of the Standard Normal distribution, lets denote it \phi , are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

P(X > 50) = P(\frac{X-50}{8.33} > \frac{50-50}{8.33}) = P(W > 0) = \phi(0) = 1/2

Download pdf
8 0
3 years ago
in a photograph alison stands next to her brother caleb. alison is 4cm tall in the photograph her actual height is 60in cale is
Dafna11 [192]
His actual height is 48 inches
4 0
3 years ago
The scale of a room in blueprint is 3in 5ft. A wall in the same blueprint is 18in. what are the actual room measurements?
QveST [7]

Answer:

Actual length of wall = 30ft

Step-by-step explanation:

We have scale of a room as 3 inch for 5ft.

We can write scaling factor as:

Scaling factor = 3 /60     (Since 5ft = 60 inches )

Scaling factor = 1/20

Now,

a wall in the blueprint is 18inch.

So actual length of wall can be determined by dividing 18 inch by the scale factor.

i.e actual length of wall = 18 / scale factor  = 18 / (1/20)

 actual length of wall = 18* 20 = 360 inch = 30ft (Since 360 inch = 30ft)

Hence Actual length of wall = 30ft

5 0
3 years ago
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