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zaharov [31]
3 years ago
9

Find the tangents of the acute angles in the right triangle

Mathematics
1 answer:
crimeas [40]3 years ago
8 0

f=50

d=40

Hope this helps

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What is the sum of all values of m that satisfy 2m (squared) -16m+8=0?
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<h2>Steps:</h2>

So for this, we will be completing the square to solve for m. Firstly, subtract 8 on both sides:

2m^2-16m=-8

Next, divide both sides by 2:

m^2-8m=-4

Next, we want to make the left side of the equation a perfect square. To find the constant of this perfect square, divide the m coefficient by 2, then square the quotient. In this case:

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Add 16 to both sides of the equation:

m^2-8m+16=12

Next, factor the left side:

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Next, square root both sides of the equation:

m-4=\pm \sqrt{12}

Next, add 4 to both sides of the equation:

m=4\pm \sqrt{12}

Now, while this is your answer, you can further simplify the radical using the product rule of radicals:

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√12 = √4 × √3 = 2√3.

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<h2>Answer:</h2>

In exact form, your answer is m=4\pm \sqrt{12}\ \textsf{OR}\ m=4\pm 2\sqrt{3}

In approximate form, your answers are (rounded to the hundreths) m=7.46, 0.54

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