Answer:
I think it is d
Step-by-step explanation:
My first rectangle is 1 unit wide and 24 units long. Its area
is 24 square units and its perimeter is 50 units.
My second rectangle is 2 units wide and 12 units long. Its area
is 24 square units and its perimeter is 28 units.
My third rectangle is 3 units wide and 8 units long. Its area
is 24 square units and its perimeter is 22 units.
My fourth rectangle is 4 units wide and 6 units long. Its area
is 24 square units and its perimeter is 20 units.
find the mean, median, and interquartile range for the data set below. 5,8,9,11,13,15,16,17,17,18,22,23
Alekssandra [29.7K]
Answer:
Mean: 14.5
Median: 15.5
IQR = 7.5
Step-by-step explanation:
For mean:
Mean= (∑x)/n
=(5+8+9+11+13+15+16+17+17+18+22+23)/12
= 174/12
=14.5
Median:
As the data is already sorted and the number of items are odd, average of two middle values will be the median of the data.
5,8,9,11,13,15,16,17,17,18,22,23
Median=(15+16)/2
=31/2
=15.5
IQR:
For IQR, the data has to be divided in two parts, lower and upper, then we have to find the median of both parts separately. The difference of medians of both parts is called the Interquartile range.
So for lower part,
5,8,9,11,13,15
Median for lower part= (9+11)/2
= 20/2
=10
For upper part:
16,17,17,18,22,23
Median for lower part= (17+18)/2
= 35/2
=17.5
IQR=17.5-10
=7.5
If you're doing kilometers per HOUR then the answer would be 2.25 just do 1991.25 divided by 885.
ANSWER : 2.25